2(3x-2)+2(x)=28

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Solution for 2(3x-2)+2(x)=28 equation: 



2(3x-2)+2(x)=28

We move all terms to the left:

2(3x-2)+2(x)-(28)=0

We add all the numbers together, and all the variables

2x+2(3x-2)-28=0

We multiply parentheses

2x+6x-4-28=0

We add all the numbers together, and all the variables

8x-32=0

We move all terms containing x to the left, all other terms to the right

8x=32

x=32/8

x=4

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