2(3x-2)+4(x+3)=3(4-2x)

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Solution for 2(3x-2)+4(x+3)=3(4-2x) equation: 



2(3x-2)+4(x+3)=3(4-2x)

We move all terms to the left:

2(3x-2)+4(x+3)-(3(4-2x))=0

We add all the numbers together, and all the variables

2(3x-2)+4(x+3)-(3(-2x+4))=0

We multiply parentheses

6x+4x-(3(-2x+4))-4+12=0



We calculate terms in parentheses: -(3(-2x+4)), so:

3(-2x+4)

We multiply parentheses

-6x+12

Back to the equation:

-(-6x+12)



We add all the numbers together, and all the variables

10x-(-6x+12)+8=0

We get rid of parentheses

10x+6x-12+8=0

We add all the numbers together, and all the variables

16x-4=0

We move all terms containing x to the left, all other terms to the right

16x=4

x=4/16

x=1/4

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