2(3x-2)+4(x+5)=56

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Solution for 2(3x-2)+4(x+5)=56 equation: 



2(3x-2)+4(x+5)=56

We move all terms to the left:

2(3x-2)+4(x+5)-(56)=0

We multiply parentheses

6x+4x-4+20-56=0

We add all the numbers together, and all the variables

10x-40=0

We move all terms containing x to the left, all other terms to the right

10x=40

x=40/10

x=4

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