2(3x-2)+5=-6(4-x)+25

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Solution for 2(3x-2)+5=-6(4-x)+25 equation: 



2(3x-2)+5=-6(4-x)+25

We move all terms to the left:

2(3x-2)+5-(-6(4-x)+25)=0

We add all the numbers together, and all the variables

2(3x-2)-(-6(-1x+4)+25)+5=0

We multiply parentheses

6x-(-6(-1x+4)+25)-4+5=0



We calculate terms in parentheses: -(-6(-1x+4)+25), so:

-6(-1x+4)+25

We multiply parentheses

6x-24+25

We add all the numbers together, and all the variables

6x+1

Back to the equation:

-(6x+1)



We add all the numbers together, and all the variables

6x-(6x+1)+1=0

We get rid of parentheses

6x-6x-1+1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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