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2(3x-2)+7/2=5x-2(2x-7
We move all terms to the left:
2(3x-2)+7/2-(5x-2(2x-7)=0
We multiply parentheses
6x-(5x-2(2x-7)+7/2-4=0
We multiply all the terms by the denominator
6x*2-(5x-2(2x-7)+7-4=0
Wy multiply elements
12x-(5x-2(2x-7)+7-4=0
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