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2(3x-2)-2=2(x-3)+32
We move all terms to the left:
2(3x-2)-2-(2(x-3)+32)=0
We multiply parentheses
6x-(2(x-3)+32)-4-2=0
We calculate terms in parentheses: -(2(x-3)+32), so:We add all the numbers together, and all the variables
2(x-3)+32
We multiply parentheses
2x-6+32
We add all the numbers together, and all the variables
2x+26
Back to the equation:
-(2x+26)
6x-(2x+26)-6=0
We get rid of parentheses
6x-2x-26-6=0
We add all the numbers together, and all the variables
4x-32=0
We move all terms containing x to the left, all other terms to the right
4x=32
x=32/4
x=8
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