2(3x-2)=16x-64

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Solution for 2(3x-2)=16x-64 equation:



2(3x-2)=16x-64
We move all terms to the left:
2(3x-2)-(16x-64)=0
We multiply parentheses
6x-(16x-64)-4=0
We get rid of parentheses
6x-16x+64-4=0
We add all the numbers together, and all the variables
-10x+60=0
We move all terms containing x to the left, all other terms to the right
-10x=-60
x=-60/-10
x=+6

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