2(3x-2)=5(2x+1)=x-4

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Solution for 2(3x-2)=5(2x+1)=x-4 equation: 



2(3x-2)=5(2x+1)=x-4

We move all terms to the left:

2(3x-2)-(5(2x+1))=0

We multiply parentheses

6x-(5(2x+1))-4=0



We calculate terms in parentheses: -(5(2x+1)), so:

5(2x+1)

We multiply parentheses

10x+5

Back to the equation:

-(10x+5)



We get rid of parentheses

6x-10x-5-4=0

We add all the numbers together, and all the variables

-4x-9=0

We move all terms containing x to the left, all other terms to the right

-4x=9

x=9/-4

x=-2+1/4

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