2(3x-20)=2(x+16)

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Solution for 2(3x-20)=2(x+16) equation: 



2(3x-20)=2(x+16)

We move all terms to the left:

2(3x-20)-(2(x+16))=0

We multiply parentheses

6x-(2(x+16))-40=0



We calculate terms in parentheses: -(2(x+16)), so:

2(x+16)

We multiply parentheses

2x+32

Back to the equation:

-(2x+32)



We get rid of parentheses

6x-2x-32-40=0

We add all the numbers together, and all the variables

4x-72=0

We move all terms containing x to the left, all other terms to the right

4x=72

x=72/4

x=18

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