2(3x-23)-3=3(4x+2)-5

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Solution for 2(3x-23)-3=3(4x+2)-5 equation: 



2(3x-23)-3=3(4x+2)-5

We move all terms to the left:

2(3x-23)-3-(3(4x+2)-5)=0

We multiply parentheses

6x-(3(4x+2)-5)-46-3=0



We calculate terms in parentheses: -(3(4x+2)-5), so:

3(4x+2)-5

We multiply parentheses

12x+6-5

We add all the numbers together, and all the variables

12x+1

Back to the equation:

-(12x+1)



We add all the numbers together, and all the variables

6x-(12x+1)-49=0

We get rid of parentheses

6x-12x-1-49=0

We add all the numbers together, and all the variables

-6x-50=0

We move all terms containing x to the left, all other terms to the right

-6x=50

x=50/-6

x=-8+1/3

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