2(3x-3)-2=2(x-2)+12

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Solution for 2(3x-3)-2=2(x-2)+12 equation: 



2(3x-3)-2=2(x-2)+12

We move all terms to the left:

2(3x-3)-2-(2(x-2)+12)=0

We multiply parentheses

6x-(2(x-2)+12)-6-2=0



We calculate terms in parentheses: -(2(x-2)+12), so:

2(x-2)+12

We multiply parentheses

2x-4+12

We add all the numbers together, and all the variables

2x+8

Back to the equation:

-(2x+8)



We add all the numbers together, and all the variables

6x-(2x+8)-8=0

We get rid of parentheses

6x-2x-8-8=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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