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2(3x-3)-5=2(x-5)+23
We move all terms to the left:
2(3x-3)-5-(2(x-5)+23)=0
We multiply parentheses
6x-(2(x-5)+23)-6-5=0
We calculate terms in parentheses: -(2(x-5)+23), so:We add all the numbers together, and all the variables
2(x-5)+23
We multiply parentheses
2x-10+23
We add all the numbers together, and all the variables
2x+13
Back to the equation:
-(2x+13)
6x-(2x+13)-11=0
We get rid of parentheses
6x-2x-13-11=0
We add all the numbers together, and all the variables
4x-24=0
We move all terms containing x to the left, all other terms to the right
4x=24
x=24/4
x=6
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