2(3x-3)=2x+22

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Solution for 2(3x-3)=2x+22 equation: 



2(3x-3)=2x+22

We move all terms to the left:

2(3x-3)-(2x+22)=0

We multiply parentheses

6x-(2x+22)-6=0

We get rid of parentheses

6x-2x-22-6=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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