2(3x-3)=3(x+2)

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Solution for 2(3x-3)=3(x+2) equation: 



2(3x-3)=3(x+2)

We move all terms to the left:

2(3x-3)-(3(x+2))=0

We multiply parentheses

6x-(3(x+2))-6=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

6x-3x-6-6=0

We add all the numbers together, and all the variables

3x-12=0

We move all terms containing x to the left, all other terms to the right

3x=12

x=12/3

x=4

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