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2(3x-4)+-3(x+1)=5
We move all terms to the left:
2(3x-4)+-3(x+1)-(5)=0
determiningTheFunctionDomain 2(3x-4)-3(x+1)-5+=0
We add all the numbers together, and all the variables
2(3x-4)-3(x+1)=0
We multiply parentheses
6x-3x-8-3=0
We add all the numbers together, and all the variables
3x-11=0
We move all terms containing x to the left, all other terms to the right
3x=11
x=11/3
x=3+2/3
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