2(3x-4)+12=3x=5x+20

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Solution for 2(3x-4)+12=3x=5x+20 equation: 



2(3x-4)+12=3x=5x+20

We move all terms to the left:

2(3x-4)+12-(3x)=0

We add all the numbers together, and all the variables

-3x+2(3x-4)+12=0

We multiply parentheses

-3x+6x-8+12=0

We add all the numbers together, and all the variables

3x+4=0

We move all terms containing x to the left, all other terms to the right

3x=-4

x=-4/3

x=-1+1/3

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