2(3x-4)+12=64

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Solution for 2(3x-4)+12=64 equation: 



2(3x-4)+12=64

We move all terms to the left:

2(3x-4)+12-(64)=0

We add all the numbers together, and all the variables

2(3x-4)-52=0

We multiply parentheses

6x-8-52=0

We add all the numbers together, and all the variables

6x-60=0

We move all terms containing x to the left, all other terms to the right

6x=60

x=60/6

x=10

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