2(3x-4)+2=1/3(36x-12)+2

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Solution for 2(3x-4)+2=1/3(36x-12)+2 equation: 



2(3x-4)+2=1/3(36x-12)+2

We move all terms to the left:

2(3x-4)+2-(1/3(36x-12)+2)=0



Domain of the equation: 3(36x-12)+2)!=0

x∈R



We multiply parentheses

6x-(1/3(36x-12)+2)-8+2=0

We multiply all the terms by the denominator


6x*3(36x-12)-8*3(36x-12)+2)+2*3(36x+2)-(1-12)+2)=0

We add all the numbers together, and all the variables

6x*3(36x-12)-8*3(36x-12)+2)+2*3(36x+2)-(-11)+2)=0

We add all the numbers together, and all the variables

6x*3(36x-12)-8*3(36x-12)+2)+2*3(36x=0

Wy multiply elements

18x^2(3-24x(3+2)+2*3(36x=0

We add all the numbers together, and all the variables

18x^2(3-24x5+2*3(36x=0

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