2(3x-4)+2=1/3(36x-12)+2

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Solution for 2(3x-4)+2=1/3(36x-12)+2 equation:



2(3x-4)+2=1/3(36x-12)+2
We move all terms to the left:
2(3x-4)+2-(1/3(36x-12)+2)=0
Domain of the equation: 3(36x-12)+2)!=0
x∈R
We multiply parentheses
6x-(1/3(36x-12)+2)-8+2=0
We multiply all the terms by the denominator
6x*3(36x-12)-8*3(36x-12)+2)+2*3(36x+2)-(1-12)+2)=0
We add all the numbers together, and all the variables
6x*3(36x-12)-8*3(36x-12)+2)+2*3(36x+2)-(-11)+2)=0
We add all the numbers together, and all the variables
6x*3(36x-12)-8*3(36x-12)+2)+2*3(36x=0
Wy multiply elements
18x^2(3-24x(3+2)+2*3(36x=0
We add all the numbers together, and all the variables
18x^2(3-24x5+2*3(36x=0

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