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2(3x-4)+2=10x-2(2x+4)
We move all terms to the left:
2(3x-4)+2-(10x-2(2x+4))=0
We multiply parentheses
6x-(10x-2(2x+4))-8+2=0
We calculate terms in parentheses: -(10x-2(2x+4)), so:We add all the numbers together, and all the variables
10x-2(2x+4)
We multiply parentheses
10x-4x-8
We add all the numbers together, and all the variables
6x-8
Back to the equation:
-(6x-8)
6x-(6x-8)-6=0
We get rid of parentheses
6x-6x+8-6=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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