2(3x-4)+5(x+6)=7(x+3)-10

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Solution for 2(3x-4)+5(x+6)=7(x+3)-10 equation: 



2(3x-4)+5(x+6)=7(x+3)-10

We move all terms to the left:

2(3x-4)+5(x+6)-(7(x+3)-10)=0

We multiply parentheses

6x+5x-(7(x+3)-10)-8+30=0



We calculate terms in parentheses: -(7(x+3)-10), so:

7(x+3)-10

We multiply parentheses

7x+21-10

We add all the numbers together, and all the variables

7x+11

Back to the equation:

-(7x+11)



We add all the numbers together, and all the variables

11x-(7x+11)+22=0

We get rid of parentheses

11x-7x-11+22=0

We add all the numbers together, and all the variables

4x+11=0

We move all terms containing x to the left, all other terms to the right

4x=-11

x=-11/4

x=-2+3/4

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