2(3x-4)+6(x+2)=-20

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Solution for 2(3x-4)+6(x+2)=-20 equation: 



2(3x-4)+6(x+2)=-20

We move all terms to the left:

2(3x-4)+6(x+2)-(-20)=0

We add all the numbers together, and all the variables

2(3x-4)+6(x+2)+20=0

We multiply parentheses

6x+6x-8+12+20=0

We add all the numbers together, and all the variables

12x+24=0

We move all terms containing x to the left, all other terms to the right

12x=-24

x=-24/12

x=-2

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