2(3x-4)+6(x-4)=22x-7

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Solution for 2(3x-4)+6(x-4)=22x-7 equation: 



2(3x-4)+6(x-4)=22x-7

We move all terms to the left:

2(3x-4)+6(x-4)-(22x-7)=0

We multiply parentheses

6x+6x-(22x-7)-8-24=0

We get rid of parentheses

6x+6x-22x+7-8-24=0

We add all the numbers together, and all the variables

-10x-25=0

We move all terms containing x to the left, all other terms to the right

-10x=25

x=25/-10

x=-2+1/2

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