2(3x-4)+8=3(x+5)-12

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Solution for 2(3x-4)+8=3(x+5)-12 equation:



2(3x-4)+8=3(x+5)-12
We move all terms to the left:
2(3x-4)+8-(3(x+5)-12)=0
We multiply parentheses
6x-(3(x+5)-12)-8+8=0
We calculate terms in parentheses: -(3(x+5)-12), so:
3(x+5)-12
We multiply parentheses
3x+15-12
We add all the numbers together, and all the variables
3x+3
Back to the equation:
-(3x+3)
We add all the numbers together, and all the variables
6x-(3x+3)=0
We get rid of parentheses
6x-3x-3=0
We add all the numbers together, and all the variables
3x-3=0
We move all terms containing x to the left, all other terms to the right
3x=3
x=3/3
x=1

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