2(3x-4)+8x=6x-10+14x

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Solution for 2(3x-4)+8x=6x-10+14x equation:



2(3x-4)+8x=6x-10+14x
We move all terms to the left:
2(3x-4)+8x-(6x-10+14x)=0
We add all the numbers together, and all the variables
2(3x-4)+8x-(20x-10)=0
We add all the numbers together, and all the variables
8x+2(3x-4)-(20x-10)=0
We multiply parentheses
8x+6x-(20x-10)-8=0
We get rid of parentheses
8x+6x-20x+10-8=0
We add all the numbers together, and all the variables
-6x+2=0
We move all terms containing x to the left, all other terms to the right
-6x=-2
x=-2/-6
x=1/3

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