2(3x-4)-(6-2x)=3(x+2)

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Solution for 2(3x-4)-(6-2x)=3(x+2) equation: 



2(3x-4)-(6-2x)=3(x+2)

We move all terms to the left:

2(3x-4)-(6-2x)-(3(x+2))=0

We add all the numbers together, and all the variables

2(3x-4)-(-2x+6)-(3(x+2))=0

We multiply parentheses

6x-(-2x+6)-(3(x+2))-8=0

We get rid of parentheses

6x+2x-(3(x+2))-6-8=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

8x-(3x+6)-14=0

We get rid of parentheses

8x-3x-6-14=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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