2(3x-4)-(x-7)=-6(x+1)+7x

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Solution for 2(3x-4)-(x-7)=-6(x+1)+7x equation: 



2(3x-4)-(x-7)=-6(x+1)+7x

We move all terms to the left:

2(3x-4)-(x-7)-(-6(x+1)+7x)=0

We multiply parentheses

6x-(x-7)-(-6(x+1)+7x)-8=0

We get rid of parentheses

6x-x-(-6(x+1)+7x)+7-8=0



We calculate terms in parentheses: -(-6(x+1)+7x), so:

-6(x+1)+7x

We add all the numbers together, and all the variables

7x-6(x+1)

We multiply parentheses

7x-6x-6

We add all the numbers together, and all the variables

x-6

Back to the equation:

-(x-6)



We add all the numbers together, and all the variables

5x-(x-6)-1=0

We get rid of parentheses

5x-x+6-1=0

We add all the numbers together, and all the variables

4x+5=0

We move all terms containing x to the left, all other terms to the right

4x=-5

x=-5/4

x=-1+1/4

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