2(3x-4)-(x-7)=6(x+1)+7x

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Solution for 2(3x-4)-(x-7)=6(x+1)+7x equation: 



2(3x-4)-(x-7)=6(x+1)+7x

We move all terms to the left:

2(3x-4)-(x-7)-(6(x+1)+7x)=0

We multiply parentheses

6x-(x-7)-(6(x+1)+7x)-8=0

We get rid of parentheses

6x-x-(6(x+1)+7x)+7-8=0



We calculate terms in parentheses: -(6(x+1)+7x), so:

6(x+1)+7x

We add all the numbers together, and all the variables

7x+6(x+1)

We multiply parentheses

7x+6x+6

We add all the numbers together, and all the variables

13x+6

Back to the equation:

-(13x+6)



We add all the numbers together, and all the variables

5x-(13x+6)-1=0

We get rid of parentheses

5x-13x-6-1=0

We add all the numbers together, and all the variables

-8x-7=0

We move all terms containing x to the left, all other terms to the right

-8x=7

x=7/-8

x=-7/8

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