2(3x-4)-2(2x+2)=-4(x+2)-3

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Solution for 2(3x-4)-2(2x+2)=-4(x+2)-3 equation: 



2(3x-4)-2(2x+2)=-4(x+2)-3

We move all terms to the left:

2(3x-4)-2(2x+2)-(-4(x+2)-3)=0

We multiply parentheses

6x-4x-(-4(x+2)-3)-8-4=0



We calculate terms in parentheses: -(-4(x+2)-3), so:

-4(x+2)-3

We multiply parentheses

-4x-8-3

We add all the numbers together, and all the variables

-4x-11

Back to the equation:

-(-4x-11)



We add all the numbers together, and all the variables

2x-(-4x-11)-12=0

We get rid of parentheses

2x+4x+11-12=0

We add all the numbers together, and all the variables

6x-1=0

We move all terms containing x to the left, all other terms to the right

6x=1

x=1/6

x=1/6

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