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2(3x-4)-3=2(x-5)+19
We move all terms to the left:
2(3x-4)-3-(2(x-5)+19)=0
We multiply parentheses
6x-(2(x-5)+19)-8-3=0
We calculate terms in parentheses: -(2(x-5)+19), so:We add all the numbers together, and all the variables
2(x-5)+19
We multiply parentheses
2x-10+19
We add all the numbers together, and all the variables
2x+9
Back to the equation:
-(2x+9)
6x-(2x+9)-11=0
We get rid of parentheses
6x-2x-9-11=0
We add all the numbers together, and all the variables
4x-20=0
We move all terms containing x to the left, all other terms to the right
4x=20
x=20/4
x=5
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