2(3x-4)-4(1-3x)=3(x+4)

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Solution for 2(3x-4)-4(1-3x)=3(x+4) equation: 



2(3x-4)-4(1-3x)=3(x+4)

We move all terms to the left:

2(3x-4)-4(1-3x)-(3(x+4))=0

We add all the numbers together, and all the variables

2(3x-4)-4(-3x+1)-(3(x+4))=0

We multiply parentheses

6x+12x-(3(x+4))-8-4=0



We calculate terms in parentheses: -(3(x+4)), so:

3(x+4)

We multiply parentheses

3x+12

Back to the equation:

-(3x+12)



We add all the numbers together, and all the variables

18x-(3x+12)-12=0

We get rid of parentheses

18x-3x-12-12=0

We add all the numbers together, and all the variables

15x-24=0

We move all terms containing x to the left, all other terms to the right

15x=24

x=24/15

x=1+3/5

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