2(3x-4)-4(1-6x)=18

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Solution for 2(3x-4)-4(1-6x)=18 equation: 



2(3x-4)-4(1-6x)=18

We move all terms to the left:

2(3x-4)-4(1-6x)-(18)=0

We add all the numbers together, and all the variables

2(3x-4)-4(-6x+1)-18=0

We multiply parentheses

6x+24x-8-4-18=0

We add all the numbers together, and all the variables

30x-30=0

We move all terms containing x to the left, all other terms to the right

30x=30

x=30/30

x=1

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