2(3x-4)-6=3+(-x+2)

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Solution for 2(3x-4)-6=3+(-x+2) equation: 



2(3x-4)-6=3+(-x+2)

We move all terms to the left:

2(3x-4)-6-(3+(-x+2))=0

We add all the numbers together, and all the variables

2(3x-4)-(3+(-1x+2))-6=0

We multiply parentheses

6x-(3+(-1x+2))-8-6=0



We calculate terms in parentheses: -(3+(-1x+2)), so:

3+(-1x+2)

determiningTheFunctionDomain
(-1x+2)+3

We get rid of parentheses

-1x+2+3

We add all the numbers together, and all the variables

-1x+5

Back to the equation:

-(-1x+5)



We add all the numbers together, and all the variables

6x-(-1x+5)-14=0

We get rid of parentheses

6x+1x-5-14=0

We add all the numbers together, and all the variables

7x-19=0

We move all terms containing x to the left, all other terms to the right

7x=19

x=19/7

x=2+5/7

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