2(3x-4)/5=2(2x-1)/3

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Solution for 2(3x-4)/5=2(2x-1)/3 equation: 



2(3x-4)/5=2(2x-1)/3

We move all terms to the left:

2(3x-4)/5-(2(2x-1)/3)=0

We calculate fractions


6x/()+(-(2(2x-1)*5)/()=0



We calculate terms in parentheses: +(-(2(2x-1)*5)/(), so:

-(2(2x-1)*5)/(

We multiply all the terms by the denominator


-(2(2x-1)*5)



We calculate terms in parentheses: -(2(2x-1)*5), so:

2(2x-1)*5

We multiply parentheses

20x-10

Back to the equation:

-(20x-10)



We get rid of parentheses

-20x+10

Back to the equation:

+(-20x+10)



We get rid of parentheses

6x/()-20x+10=0

We multiply all the terms by the denominator


6x-20x*()+10*()=0

We add all the numbers together, and all the variables

6x-20x*()=0

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