2(3x-4)/5=2(2x-1)/3

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Solution for 2(3x-4)/5=2(2x-1)/3 equation:



2(3x-4)/5=2(2x-1)/3
We move all terms to the left:
2(3x-4)/5-(2(2x-1)/3)=0
We calculate fractions
6x/()+(-(2(2x-1)*5)/()=0
We calculate terms in parentheses: +(-(2(2x-1)*5)/(), so:
-(2(2x-1)*5)/(
We multiply all the terms by the denominator
-(2(2x-1)*5)
We calculate terms in parentheses: -(2(2x-1)*5), so:
2(2x-1)*5
We multiply parentheses
20x-10
Back to the equation:
-(20x-10)
We get rid of parentheses
-20x+10
Back to the equation:
+(-20x+10)
We get rid of parentheses
6x/()-20x+10=0
We multiply all the terms by the denominator
6x-20x*()+10*()=0
We add all the numbers together, and all the variables
6x-20x*()=0

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