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2(3x-4)=(-8-6x)
We move all terms to the left:
2(3x-4)-((-8-6x))=0
We add all the numbers together, and all the variables
2(3x-4)-((-6x-8))=0
We multiply parentheses
6x-((-6x-8))-8=0
We calculate terms in parentheses: -((-6x-8)), so:We get rid of parentheses
(-6x-8)
We get rid of parentheses
-6x-8
Back to the equation:
-(-6x-8)
6x+6x+8-8=0
We add all the numbers together, and all the variables
12x=0
x=0/12
x=0
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