2(3x-4)=(1/2x-4

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Solution for 2(3x-4)=(1/2x-4 equation: 



2(3x-4)=(1/2x-4

We move all terms to the left:

2(3x-4)-((1/2x-4)=0



Domain of the equation: 2x-4)!=0

x∈R



We multiply parentheses

6x-((1/2x-4)-8=0

We multiply all the terms by the denominator


6x*2x-4)-8-((1=0

We add all the numbers together, and all the variables

6x*2x=0

Wy multiply elements

12x^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$

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