2(3x-4)=-2(x-2)

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Solution for 2(3x-4)=-2(x-2) equation: 



2(3x-4)=-2(x-2)

We move all terms to the left:

2(3x-4)-(-2(x-2))=0

We multiply parentheses

6x-(-2(x-2))-8=0



We calculate terms in parentheses: -(-2(x-2)), so:

-2(x-2)

We multiply parentheses

-2x+4

Back to the equation:

-(-2x+4)



We get rid of parentheses

6x+2x-4-8=0

We add all the numbers together, and all the variables

8x-12=0

We move all terms containing x to the left, all other terms to the right

8x=12

x=12/8

x=1+1/2

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