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2(3x-4)=-5(x-5)
We move all terms to the left:
2(3x-4)-(-5(x-5))=0
We multiply parentheses
6x-(-5(x-5))-8=0
We calculate terms in parentheses: -(-5(x-5)), so:We get rid of parentheses
-5(x-5)
We multiply parentheses
-5x+25
Back to the equation:
-(-5x+25)
6x+5x-25-8=0
We add all the numbers together, and all the variables
11x-33=0
We move all terms containing x to the left, all other terms to the right
11x=33
x=33/11
x=3
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