2(3x-4)=1/2x-8

Solution for 2(3x-4)=1/2x-8 equation:

2(3x-4)=1/2x-8

We move all terms to the left:

2(3x-4)-(1/2x-8)=0


Domain of the equation: 2x-8)!=0

x∈R


We multiply parentheses

6x-(1/2x-8)-8=0

We get rid of parentheses

6x-1/2x+8-8=0

We multiply all the terms by the denominator


6x*2x+8*2x-8*2x-1=0

Wy multiply elements

12x^2+16x-16x-1=0

We add all the numbers together, and all the variables

12x^2-1=0

a = 12; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·12·(-1)
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{3}}{2*12}=\frac{0-4\sqrt{3}}{24}
=-\frac{4\sqrt{3}}{24}
=-\frac{\sqrt{3}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{3}}{2*12}=\frac{0+4\sqrt{3}}{24}
=\frac{4\sqrt{3}}{24}
=\frac{\sqrt{3}}{6}
$