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2(3x-4)=3(2x-1)-5
We move all terms to the left:
2(3x-4)-(3(2x-1)-5)=0
We multiply parentheses
6x-(3(2x-1)-5)-8=0
We calculate terms in parentheses: -(3(2x-1)-5), so:We get rid of parentheses
3(2x-1)-5
We multiply parentheses
6x-3-5
We add all the numbers together, and all the variables
6x-8
Back to the equation:
-(6x-8)
6x-6x+8-8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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