2(3x-4)=3(x+1)-5

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Solution for 2(3x-4)=3(x+1)-5 equation: 



2(3x-4)=3(x+1)-5

We move all terms to the left:

2(3x-4)-(3(x+1)-5)=0

We multiply parentheses

6x-(3(x+1)-5)-8=0



We calculate terms in parentheses: -(3(x+1)-5), so:

3(x+1)-5

We multiply parentheses

3x+3-5

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We get rid of parentheses

6x-3x+2-8=0

We add all the numbers together, and all the variables

3x-6=0

We move all terms containing x to the left, all other terms to the right

3x=6

x=6/3

x=2

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