2(3x-4)=3(x+4)+1

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Solution for 2(3x-4)=3(x+4)+1 equation:



2(3x-4)=3(x+4)+1
We move all terms to the left:
2(3x-4)-(3(x+4)+1)=0
We multiply parentheses
6x-(3(x+4)+1)-8=0
We calculate terms in parentheses: -(3(x+4)+1), so:
3(x+4)+1
We multiply parentheses
3x+12+1
We add all the numbers together, and all the variables
3x+13
Back to the equation:
-(3x+13)
We get rid of parentheses
6x-3x-13-8=0
We add all the numbers together, and all the variables
3x-21=0
We move all terms containing x to the left, all other terms to the right
3x=21
x=21/3
x=7

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