2(3x-4)=3x-38

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Solution for 2(3x-4)=3x-38 equation: 



2(3x-4)=3x-38

We move all terms to the left:

2(3x-4)-(3x-38)=0

We multiply parentheses

6x-(3x-38)-8=0

We get rid of parentheses

6x-3x+38-8=0

We add all the numbers together, and all the variables

3x+30=0

We move all terms containing x to the left, all other terms to the right

3x=-30

x=-30/3

x=-10

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