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2(3x-4)=4(2x+5)
We move all terms to the left:
2(3x-4)-(4(2x+5))=0
We multiply parentheses
6x-(4(2x+5))-8=0
We calculate terms in parentheses: -(4(2x+5)), so:We get rid of parentheses
4(2x+5)
We multiply parentheses
8x+20
Back to the equation:
-(8x+20)
6x-8x-20-8=0
We add all the numbers together, and all the variables
-2x-28=0
We move all terms containing x to the left, all other terms to the right
-2x=28
x=28/-2
x=-14
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