2(3x-4)=40+2x

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Solution for 2(3x-4)=40+2x equation: 



2(3x-4)=40+2x

We move all terms to the left:

2(3x-4)-(40+2x)=0

We add all the numbers together, and all the variables

2(3x-4)-(2x+40)=0

We multiply parentheses

6x-(2x+40)-8=0

We get rid of parentheses

6x-2x-40-8=0

We add all the numbers together, and all the variables

4x-48=0

We move all terms containing x to the left, all other terms to the right

4x=48

x=48/4

x=12

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