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2(3x-4)=5(x+10)
We move all terms to the left:
2(3x-4)-(5(x+10))=0
We multiply parentheses
6x-(5(x+10))-8=0
We calculate terms in parentheses: -(5(x+10)), so:We get rid of parentheses
5(x+10)
We multiply parentheses
5x+50
Back to the equation:
-(5x+50)
6x-5x-50-8=0
We add all the numbers together, and all the variables
x-58=0
We move all terms containing x to the left, all other terms to the right
x=58
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