2(3x-4)=6-4(12-x)

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Solution for 2(3x-4)=6-4(12-x) equation: 



2(3x-4)=6-4(12-x)

We move all terms to the left:

2(3x-4)-(6-4(12-x))=0

We add all the numbers together, and all the variables

2(3x-4)-(6-4(-1x+12))=0

We multiply parentheses

6x-(6-4(-1x+12))-8=0



We calculate terms in parentheses: -(6-4(-1x+12)), so:

6-4(-1x+12)

determiningTheFunctionDomain
-4(-1x+12)+6

We multiply parentheses

4x-48+6

We add all the numbers together, and all the variables

4x-42

Back to the equation:

-(4x-42)



We get rid of parentheses

6x-4x+42-8=0

We add all the numbers together, and all the variables

2x+34=0

We move all terms containing x to the left, all other terms to the right

2x=-34

x=-34/2

x=-17

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