2(3x-4)=8x+11

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Solution for 2(3x-4)=8x+11 equation: 



2(3x-4)=8x+11

We move all terms to the left:

2(3x-4)-(8x+11)=0

We multiply parentheses

6x-(8x+11)-8=0

We get rid of parentheses

6x-8x-11-8=0

We add all the numbers together, and all the variables

-2x-19=0

We move all terms containing x to the left, all other terms to the right

-2x=19

x=19/-2

x=-9+1/2

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