2(3x-4)=x+12

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Solution for 2(3x-4)=x+12 equation: 



2(3x-4)=x+12

We move all terms to the left:

2(3x-4)-(x+12)=0

We multiply parentheses

6x-(x+12)-8=0

We get rid of parentheses

6x-x-12-8=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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