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2(3x-4+10)=5(x+4)
We move all terms to the left:
2(3x-4+10)-(5(x+4))=0
We add all the numbers together, and all the variables
2(3x+6)-(5(x+4))=0
We multiply parentheses
6x-(5(x+4))+12=0
We calculate terms in parentheses: -(5(x+4)), so:We get rid of parentheses
5(x+4)
We multiply parentheses
5x+20
Back to the equation:
-(5x+20)
6x-5x-20+12=0
We add all the numbers together, and all the variables
x-8=0
We move all terms containing x to the left, all other terms to the right
x=8
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