2(3x-46)+12=100

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Solution for 2(3x-46)+12=100 equation: 



2(3x-46)+12=100

We move all terms to the left:

2(3x-46)+12-(100)=0

We add all the numbers together, and all the variables

2(3x-46)-88=0

We multiply parentheses

6x-92-88=0

We add all the numbers together, and all the variables

6x-180=0

We move all terms containing x to the left, all other terms to the right

6x=180

x=180/6

x=30

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